1# Copyright (c) 2015 ARM Limited 2# All rights reserved. 3# 4# The license below extends only to copyright in the software and shall 5# not be construed as granting a license to any other intellectual 6# property including but not limited to intellectual property relating 7# to a hardware implementation of the functionality of the software 8# licensed hereunder. You may use the software subject to the license 9# terms below provided that you ensure that this notice is replicated 10# unmodified and in its entirety in all distributions of the software, 11# modified or unmodified, in source code or in binary form. 12# 13# Redistribution and use in source and binary forms, with or without 14# modification, are permitted provided that the following conditions are 15# met: redistributions of source code must retain the above copyright 16# notice, this list of conditions and the following disclaimer; 17# redistributions in binary form must reproduce the above copyright 18# notice, this list of conditions and the following disclaimer in the 19# documentation and/or other materials provided with the distribution; 20# neither the name of the copyright holders nor the names of its 21# contributors may be used to endorse or promote products derived from 22# this software without specific prior written permission. 23# 24# THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS 25# "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT 26# LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR 27# A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT 28# OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, 29# SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT 30# LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, 31# DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY 32# THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT 33# (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE 34# OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. 35# 36# Authors: Andreas Sandberg 37 38from __future__ import print_function 39 40from multiprocessing import Process 41import sys 42import os 43 44import m5 45 46_exit_normal = ( 47 "target called exit()", 48 "m5_exit instruction encountered", 49 ) 50 51_exit_limit = ( 52 "simulate() limit reached", 53 ) 54 55_exitcode_done = 0 56_exitcode_fail = 1 57_exitcode_checkpoint = 42 58 59 60def _run_step(name, restore=None, interval=0.5): 61 """ 62 Instantiate (optionally from a checkpoint if restore is set to the 63 checkpoitn name) the system and run for interval seconds of 64 simulated time. At the end of the simulation interval, create a 65 checkpoint and exit. 66 67 As this function is intended to run in its own process using the 68 multiprocessing framework, the exit is a true call to exit which 69 terminates the process. Exit codes are used to pass information to 70 the parent. 71 """ 72 if restore is not None: 73 m5.instantiate(restore) 74 else: 75 m5.instantiate() 76 77 e = m5.simulate(m5.ticks.fromSeconds(interval)) 78 cause = e.getCause() 79 if cause in _exit_limit: 80 m5.checkpoint(name) 81 sys.exit(_exitcode_checkpoint) 82 elif cause in _exit_normal: 83 sys.exit(_exitcode_done) 84 else: 85 print("Test failed: Unknown exit cause: %s" % cause) 86 sys.exit(_exitcode_fail) 87 88def run_test(root, interval=0.5, max_checkpoints=5): 89 """ 90 Run the simulated system for a fixed amount of time and take a 91 checkpoint, then restore from the same checkpoint and run until 92 the system calls m5 exit. 93 """ 94 95 cpt_name = os.path.join(m5.options.outdir, "test.cpt") 96 restore = None 97 98 for cpt_no in range(max_checkpoints): 99 # Create a checkpoint from a separate child process. This enables 100 # us to get back to a (mostly) pristine state and restart 101 # simulation from the checkpoint. 102 p = Process(target=_run_step, 103 args=(cpt_name, ), 104 kwargs={ 105 "restore" : restore, 106 "interval" : interval, 107 }) 108 p.start() 109 110 # Wait for the child to return 111 p.join() 112 113 # Restore from the checkpoint next iteration 114 restore = cpt_name 115 116 if p.exitcode == _exitcode_done: 117 print("Test done.", file=sys.stderr) 118 sys.exit(0) 119 elif p.exitcode == _exitcode_checkpoint: 120 pass 121 else: 122 print("Test failed.", file=sys.stderr) 123 sys.exit(1) 124 125 # Maximum number of checkpoints reached. Just run full-speed from 126 # now on. 127 m5.instantiate() 128 e = m5.simulate() 129 cause = e.getCause() 130 if cause in _exit_normal: 131 sys.exit(0) 132 else: 133 print("Test failed: Unknown exit cause: %s" % cause) 134 sys.exit(1) 135